[데이터 베이스] 10-1. 순위 구하기 Rank () over 함수

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Feb 28, 2025
[데이터 베이스] 10-1. 순위 구하기 
Rank () over 함수
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rank () over, row_number(), set @rownum := 0

Rank () over 함수

-- DB 고급 함수 -- 1. RANK select empno, ename, sal, 1 '순위번호' from emp order by sal desc; select empno, ename, sal, rank () over (order by sal desc) '순위' from emp; select empno, ename, sal, dense_rank () over (order by sal desc) '순위' from emp; select empno, ename, sal, row_number () over (order by sal desc) '순위' -- 순차적으로 숫자를 붙이는 것, 넘버링하기 from emp;
order by sal desc;
order by sal desc;
dense_rank () over (order by sal desc)
dense_rank () over (order by sal desc)
rank () over (order by sal desc)
rank () over (order by sal desc)
row_number () over (order by sal desc)
row_number () over (order by sal desc)

Rank () over 함수 응용 문제

-- 2. 문제 (EMP 테이블에서, 본인의 월급과 상사의 월급의 합의 순위를 내림차순으로 구하시오) select e1.ename, e1.sal '내월급', e2.sal '상사월급', e1.sal+ifnull(e2.sal,0) '월급의합', dense_rank() over (order by e1.sal+ifnull(e2.sal,0) desc) '순위' from emp e1 left outer join emp e2 on e1.mgr = e2.empno; select 나, 상사, 내월급, 상사월급, rank() over (order by 상사월급 desc) '순위' from ( select e1.ename '나', e2.ename '상사', e1.sal '내월급', e2.sal '상사월급', e1.sal+ifnull(e2.sal, 0) '월급의합' from emp e1 left outer join emp e2 on e1.mgr = e2.empno ) nemp;
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